# Column Formwork Scaffolding Design Example

Wooden scaffolding calculation will be made for the 30x60 column of the project, which includes the plan and 3D model image.

• Plywood thickness t=18 mm,

• Plywood Flexural strength fel = 30 MPa

• Plywood Shear strength fek = 3.0 MPa

• Plywood Modulus of Elasticity El = 10000 MPa

• Concrete placing speed in the formwork R = 2m/hour

• Concrete casting temperature T = 20°C

Ƥmax = p = 58.5 kN/m2 = 0.0585 N/mm2

Primary beam interval, Lbk

• bl = 1000 mm tl = 18 mm

• Al = tl * bl = 18x1000 = 18000 mm2

• Il = [ bl * ( tl ^3) ]/ 12 = 486000 mm4

• Sl = Il / ( tl / 2)= 54000 mm3

• Ƥmax = p = 58.5 kN/m2 = 0.0585 N/mm2

Secondary beam interval, Lik

H20 was chosen as the primary beam section.

• Abk = 9640 mm2

• Ibk = 45701333.333 mm4

• Sbk = 457013.333 mm3

Primary Beam material properties

• febk = 30 MPa

• febk = 3.0 MPa

• Ebk = 14000 MPa

• Lbk = 364.3mm

• Abk = 9640 mm2

• Ibk = 45701333.333 mm4

• Sbk = 457013.333 mm3

• febk = 30 MPa

• febk = 3.0 MPa

• Ebk = 14000 MPa

Rod Interval, Lb

2xUPN 80 was chosen as the secondary beam section.

• Aik = 2185.3 mm2

• Lik = 2.0921x10 6 mm4

• Sik = 52303 mm3

Secondary Beam material properties

• feik = 235 MPa

• feq = 141 MPa

• Eik = 200000 MPa

• Rod diameter Φ = 17 mm

• Lik = 753.8 mm

• Aik = 2185.3 mm2

• Iik= 2.0921x10 6 mm4

• Sik = 52303 mm3

• feik = 30 MPa

• feik = 3.0 MPa

• Eik = 14000 MPa

• Rod diameter Φ = 17 mm

• Rod tensile capacity, Nd,b

• Nd,b = [ ( π* 2 ) / 4 fyb = [ ( π*172 ) / 4 ] 235 = 53340.32 N = 53.34 kN

Prop Control

• Axial load capacity of the support Nd = 9.7 kN

• c = 1.2

• q = 0.5 kN/m 2

In a 30/60 column, the worst case will occur on the 60 cm side.

• w = q x c x b = 1.2 x 0.5 x 0.6 = 0.36 kN/m

• W = w x h = 0.36 x 3 =1.08 kN

• Npc = 1,278 kN < Nd = 9.7 kN

Example of scaffolding drawings

JavaScript errors detected